[DB] run all Forgejo migrations in integration tests
The tests at tests/integration/migration-test/migration_test.go will not run any Forgejo migration when using the gitea-*.sql.gz files because they do not contain a ForgejoVersion row which is interpreted as a new Forgejo installation for which there is no need for migration. Create a situation by which the ForgejoVersion table exists and has a version of 0 in tests/integration/migration-test/forgejo-v1.19.0.*.sql.gz thus ensuring all Forgejo migrations are run. The forgejo*.sql.gz files do not have any Gitea related records, which will be interpreted by the Gitea migrations as a new installation that does not need any migration. As a consequence the migration tests run when using forgejo-v1.19.0.*.sql.gz are exclusively about Forgejo migrations. (cherry picked from commitec8003859c
) (cherry picked from commit697570ff39
) (cherry picked from commitf041aec172
) (cherry picked from commit60463e3bab
) (cherry picked from commitb2fc2a7c13
) (cherry picked from commitfb2759b6af
) (cherry picked from commit37cfc3b227
) (cherry picked from commit832607500a
) (cherry picked from commit143d4007b1
) (cherry picked from commita17e803fbf
)
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@ -98,7 +98,7 @@ func availableVersions() ([]string, error) {
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return nil, err
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}
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defer migrationsDir.Close()
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versionRE, err := regexp.Compile("gitea-v(?P<version>.+)\\." + regexp.QuoteMeta(setting.Database.Type.String()) + "\\.sql.gz")
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versionRE, err := regexp.Compile(".*-v(?P<version>.+)\\." + regexp.QuoteMeta(setting.Database.Type.String()) + "\\.sql.gz")
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if err != nil {
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return nil, err
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}
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@ -122,7 +122,10 @@ func readSQLFromFile(version string) (string, error) {
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filename := fmt.Sprintf("tests/integration/migration-test/gitea-v%s.%s.sql.gz", version, setting.Database.Type)
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if _, err := os.Stat(filename); os.IsNotExist(err) {
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return "", nil
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filename = fmt.Sprintf("tests/integration/migration-test/forgejo-v%s.%s.sql.gz", version, setting.Database.Type)
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if _, err := os.Stat(filename); os.IsNotExist(err) {
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return "", nil
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}
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}
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file, err := os.Open(filename)
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